Question 494558
You are the 3rd or 4th person in the past week
to post this problem.  This is the answer I
gave to the others.
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Cheers,
Stan H.
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(A) Find the binomial probability P(x = 5), where n = 14 and p = 0.70.
Ans: 14C5(0.7)^5(0.3)^9 = binompdf(14,0.7,5) = 0.00660.7746
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(B) Set up, without solving, the binomial probability P(x is at most 5) using probability notation.
P(0<= x <=5) = 14C0(0.7)^0*(0.3)^14+14C1(0.7)*(0.3)^13+ etc.
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(C) How would you find the normal approximation to the binomial probability P(x = 5) in part A? 
Please show how you would calculate µ and &#963; in the formula for the normal approximation to the binomial, and show the final formula you would use without going through all the calculations

u = np = 14*0.7 = 2
s = sqrt(npq) = sqrt(2*0.3) = 0.7746
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binomial probability (x = 5)
equals normal approximation probability (4.5 < x < 5.5)
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Cheers,
Stan H.
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