Question 494263
Find the equation of the straight line with gradient -2/3 
and passing through (-3,5). 
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Form: y = mx + b
Solve for "b":
5 = (-2/3)*(-3) + b
b = 3
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Equation:
y = (-2/3)x +3
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If this line also passes through the point (A,3), find A.
3 = (-2/3)A + 3
(-2/3)A = 0
A = 0
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Cheers,
Stan H.