Question 493785
Let's give these three numbers a name, since we do not know anything else about these numbers.   Let's call the first number x, second y, and third z.

So we know that {{{x+y+z = 62}}}.

We also know that {{{y=x-4}}}.

And we also know that {{{z=4x}}}

Now notice that we have x,y,z all in terms of x.

So, {{{x+(x-4)+4x = 62}}}.

Simplify.

{{{6x -4 = 62}}}
{{{6x = 66}}}
{{{x = 11}}}
But is x our smallest value?

We know that y = x-4. So y is smaller than x, and in fact it is 7 (by substitution).

We know that z =4x, so z = 44. 44 is in fact larger than 11 and 7.

So your answer is 44.

Let's make sure that these numbers add back up to 62.

44+11+7 = 62  is TRUE.

Thus 44 is the largest number.