Question 493655
Two ships depart a port at the same time. 
One travels 11 degrees west of south at 45 mph 
x component: cos(270-11) = cos(259) = -0.1908
y component: sin(259) = -0.9816
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West distance: 45*(73/60)(-0.1908) = -10.45 miles
South distance: 45*(73/60)(-9816) = -53.74
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while the other travels 22 degrees north of east at 21 mph.
x component: cos(22) = 0.9272
y component: sin(22) = 0.3746
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Each distance: 21*73/60*0.9272 = 23.70
North distance: 21*(73/60)*0.3746 = 9.57

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 How far apart are they after 73 minutes? 
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d = sqrt[(-10.45-23.70)^2 + (-52.74-9.57)^2]
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d = sqrt[1166.22 + 3882.69]
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d = 71.06 miles
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Cheers,
Stan H.