Question 50413
V=(2/3)pi r^2(2h-r)
r^2(2h-r)=(3/2)V/pi)
r^2(2h-r)=[3V/2pi]
2h=[(3V/(2pi r^2)]+r
h=[(3V/4(pi)r^2]+(r/2)
h=[3V+2(pi)r^3]/[4(pi)r^2]
This answer may not be in the form your answer
book gives.  There are many possible forms.
Cheers,
Stan H.