Question 493381
1/(x+4) + 3/(x-4) = (3x+8)/(x^2-16)
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Multiply thru by x^2-16 to get:
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(x-4) + 3(x+4) = 3x+8
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x-4 + 3x+12 = 3x+8
4x + 8 = 3x + 8
x = 0
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Cheers,
Stan H.
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