Question 492776
Suppose 75% of chemotherapy patients suffer nausea. We randomly select two such patients (assume these two patients are independent).
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i) Find the probability that both suffer nausea:::(3/4)^2 = 9/16
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ii) Find the probability that at least one suffers nausea::: 
Ans = 1- (1/4)^2
= 1-1/16
= 15/16
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Cheers,
Stan H.
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