Question 492328
How do you solve the following problem: 
If 90degrees < 0 < 180degrees and sin 0 = 10/26, then cos 0 
**
sim x=10/26
This means you are working with a right triangle in quadrant II where sin is >0 and cos<0.
hypotenuse=26
opposite side=10
adjacent side=&#8730;(26^2-10^2)=&#8730;576=24
cos x=-24/26