Question 492650
1. It's not enough to divide 2 into 8, you have to keep numerator and denominator straight.  1/4 not 4.  Exponent OK unless they prefer 1/x^2 to x^-2.
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2. Similar; 3^-2 is not 9 but 1/9.  (y^-2)^-2 is y^4, not y^-4.
4^-2 is 1/16 not 16.
Then x^-8/x^10 is 1/x^18 not 1/x^2.
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3. I assume (3/8)y [typo].
4 * (3/8) is 3/2, not 6.
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4. |x-6|<=-8
No solution is obvious right away, |anything|>=0, can't be < a negative.
Your work is OK, just another way of getting to No Solution.
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The good news is that if you are just more careful with the numerator v. denominator, 1 2 3 will go much better.