Question 6265
<font face = "courier new" size = 2>A chemist has two solutions of sulfuric acid - a 20% solution and an 80%
solution. How much of each should be used to obtain 100 liters of a 62%
solution?<b>
`
`  x liters of 20% solution contains .20x liters of H<sub>2</sub>SO<sub>4</sub>
`  y liters of 80% solution contains .80y liters of H<sub>2</sub>SO<sub>4</sub>
`100 liters of 62% solution contains .62(100) or 62 liters of H<sub>2</sub>SO<sub>4</sub>
`
`Adding up the liters of liquid:
`
` ` ` `x + y = 100
`
Adding up the liters of H<sub>2</sub>SO<sub>4</sub>
`
`.20x + .80y = 62
`
 Can you solve this system?:
`
` x + ` y = 100
.2x + .8y = 62
`
`
Answer x = 30 liters of 20%, 70 liters of 80% dolution.
`
Edwin</b>