<PRE><B>Question 490775</B>
Let x+1 is smaller odd integer
and x+3 is larger odd integer
4 times of the smaller integer = 4(x+1)
5time of the larger integer=5(x+3)

Condition says
4(x+1)=73-5(x+3)
4x+4=73-5x-15
4x+5x=73-15-4
9x=54
Divide by 9 both sides
9x/9=54/9
x=6

Smaller odd integer = x+1 
     = 6+1
     =7
Larger odd integer = x+3
                                  =6+3
                                  =9
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