Question 491891
distance = rate*time
Aircraft carrier:
time is 13 hours, 7 hours before container ship left then the 6 hours container traveled.
Let s be speed of aircraft carrier
--> d = 13s
Container ship:
time is 6 hours
speed is 5 km/h slower, so s-5
--> d = 6(s-5)
Since they are going in opposite directions, add up the distances to find how far apart they are
--> 13s + 6(s-5) = 540
Now solve for s
--> 13s +6s -30 = 540
--> 19s = 570
--> s = 30

Aircraft carrier was traveling at 30 km/h and container ship 25 km/h