Question 491749


The length {{{L}}} is {{{12}}} units more than the width {{{W}}}. 

{{{L=W+12}}}.......1

The perimeter {{{P}}} is {{{7}}} times the width {{{W}}}.

{{{P=7W}}}

------------------------

{{{P=2(L+W)}}}

{{{2(L+W)=7W}}}...replace {{{L}}} with {{{W+12}}}

{{{2(W+12+W)=7W}}}

{{{2(2W+12)=7W}}}

{{{4W+24=7W}}}

{{{24=7W-4W}}}

{{{24=3W}}}

{{{24/3=W}}}

{{{highlight(8=W)}}}

now find {{{L}}}

{{{L=W+12}}}.......1

{{{L=8+12}}}

{{{highlight(L=20)}}}

check:

{{{P=2(L+W)}}}

{{{P=2(20+8)}}}

{{{P=2(28)}}}

{{{P=56}}}

and another one

{{{P=7W}}}

{{{P=7*8}}}

{{{P=56}}}