Question 491547
Since the roots are r1=4 and r2=11 the quadratic equation will be:

{{{ax^2+bx+c=a(x-r1)(x-r2)=0}}}, assuming a=1, substituting the roots we get:

{{{(x-4)(x-11)=x^2-15x+44=0}}}

Answer:An quadratic equation with the given roots 4 and 11 is {{{x^2-15x+44=0}}}.