Question 491142
1	x	+	3	y  	=	2			
Find the slope of this line 									
make y the subject									
3	y  	=	-1	x	+	2			
Divide by 	3								
	y  	=	-0.33	x	+	0.67			
Compare this equation with y=mx+b									
slope m =	-0.33			0.8					
The slope of a line parallel to the above line will be the same									
The slope of the required line will be 			-0.33						
m=	-0.33	,point	(	0	,	0	)		
Find b by plugging the values of m & the point in									
y=mx+b									
0	=	0.00	+	b					
b=	0								
m=	-0.33								
Plug value of  the slope  and b	in y = mx +b				
The required equation isy  	=	-0.33	x	+	0		
		y  	=	-  1/ 3	x	+	0      		
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