Question 491122
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If you let *[tex \Large r] represent the number of red marbles, you can use the information given to say that there are *[tex \Large 2r] blue marbles and *[tex \Large r\ -\ 4] green marbles.  Then:


*[tex \LARGE\ \ \ \ \ \ \ \ \ \ r\ +\ 2r\ +\ (r\ -\ 4)\ =\ 28]


Solve for *[tex \Large r], then calculate *[tex \Large 2r] and *[tex \Large r\ -\ 4].


The probability of drawing a green marble on a single draw is the number of green marbles divided by the total number of marbles.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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