Question 490996
Make exponents positive
--> {{{2/(x^x) = 1}}}
--> {{{x^x = 2}}}
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This cannot be solved explicitly using elementary operations
see wolfram alpha more explanation
http://www.wolframalpha.com/input/?i=x^x+%3D+2
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You can graph y = x^x, and see where y =2.
If you know calculus you can use Newtons method to approximate the root of f(x) = x^x - 2
Approximate solution is x = 1.5596