Question 490728
1. The hypotenuse of a right triangle is 16 in. longer than the shortest side and 2 in. longer than the remaining side. Find the dimensions of this triangle. What is the length of the remaining side (in inches)?
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c = hypotenuse
a = short side, b = longer side
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c = a+16 --> a = c-16
c = b+2 --> b = c-2
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{{{c^2 = a^2 + b^2 = (c-16)^2 + (c-2)^2}}}
{{{c^2 = c^2 - 32c + 256 + c^2 - 4c + 4}}}
{{{c^2 = 2c^2 - 36c + 260}}}
{{{c^2 - 36c + 260 = 0}}}
(c - 10)*(c - 26) = 0
c = 10, c = 26
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c = 10 doesn't work since a = -6
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c = 26
b = 10
a = 24
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It's the 5, 12, 13 right triangle x2