Question 488924
Angle ACB = Angle ACD + angle DCE + angle ECB.
Angle ACD = 1/2(4x) + 5
Angle DCE = 4x
Angle ECB = x
Angle ACB = 180.
2x + 5 + 4x + x = 180
7x = 175
x = 25
Angle ACD = 1/2(100) + 5  = 55 degrees.
Angle DCE = 4(25) = 100 degrees.
Angle ECB = 25 degrees.
55 degress + 100 degrees + 25 degrees = 180 degrees.
Cleomenius.