Question 490244
Given:

 the linear equation  {{{y=-x-4}}}

find:

 the {{{y-coordinates}}} of the points ({{{-1}}}, ), ({{{2}}}, ), and ({{{-3}}}, )

the coordinates of the point are ({{{x}}},{{{y}}}); so, above you are given coordinates {{{x}}} and you need to plug them in given linear equation {{{y = -x – 4}}} to find the coordinates {{{y}}}


for the point ({{{-1}}}, ), {{{x}}} is equal to {{{-1}}}


 {{{y=-(-1)-4}}}


 {{{y=1-4}}}


{{{y=-3}}}....so, you have the point ({{{-1}}},{{{-3}}} )



for the point ({{{2}}}, ), {{{x}}} is equal to {{{2}}}


{{{y=-(2)-4}}}


 {{{y=-2-4}}}


{{{y=-6}}}....so, you have the point ({{{-1}}},{{{-6}}} )



for the point ({{{-3}}}, ), {{{x}}} is equal to {{{-3}}}


{{{y=-(-3)-4}}}


 {{{y=3-4}}}

{{{y=-1}}}....so, you have the point ({{{-1}}},{{{-1}}} )