Question 490153
How about:
{{{v^4-1296 = (v^2)^2-(6^2)^2}}} Now factor the difference of two squares:
{{{(v^2)^2-(6^2)^2 = (v^2-6^2)(v^2+6^2)}}} Now factor the difference of squares again:
{{{v^2-6^2 = (v-6)(v+6)}}} Now put it all together to get:
{{{v^4-1296 = (v-6)(v+6)(v^2+6^2)}}} or {{{(v-6)(v+6)(v^2+36)}}}