Question 50264
f(x) = ba^x + c
y = ba^x - 2
y = ba^x - 2 P(0,2)
2 = ba^0 - 2
2 = b - 2
4 = b
plug.:
y = 4*a^x - 2 P(1,4)
4 = 4*a - 2
6 = 4a
3/2 = a
plug.:
f(x) = 4(3/2)^x - 2
{{{graph(300,300,-6,6,-6,6,-2,4(3/2)^x-2)}}}