Question 490051
a=	1	,b=	-5	,c=	1		
							
b^2-4ac=	25	+	-4				
b^2-4ac=	21						
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-12+21)/(12)}}}							
x1=(	5	+	4.58	)/	2		
x1=	4.79						
x2=(	5	-4.58	) /	2			
x2= 	0.21