Question 489501
1) A) given that set A={0,1,2,3,4,5,6}, find the number of subsets that A has.s
Ans: 2*6 = 64 subsets
================================ 
B) Given the universal set S = { -4,-3,-2,-1,0,1,2,3,4} and B= {-1,0,1,2,3}, find B'
Ans: B' = {4,-4,-3,-2,}
================================ 
2) A) how many 5-letter arrangements can be formed from the letters in the word table?
Ans: 5! = 120
-------------------------------
B) if you choose one of these words, what is the probability that the last letter is e?
Ans: 4!/5! = 1/5
------------------------------- 
3) there are 7 green balls and 3 red balls in an urn. Three balls are drawn individually and replaced. Set up a probability distribution for x, the number of red balls selected.
Binomial Problem with n = 3 ; p = 3/7 : q = 4/7
P(x = 0) = (4/7)^3
P(x = 1) = 7C1(3/7)(4/7)^2 = 
P(x = 2) = 7C2(3/7)^2(4/7) = 
P(x = 3) = 7C3(3/7)^3 = 
=================================== 
 
4) A box contains 3 red balls and 4 white balls. You draw 4 balls from the box without replacing them. Set up a probability distribution for x, the number of red balls selected 
Not a binomial Problem because of no replacing.
----
P(x = 0) = 4C4/7C4
P(x = 1) = [3C1*4C3]/7C4
P(x = 1) = [3C2*4C2]/7C4
etc.
=================
5) You are dealt a 13- card bridge hand from a deck of 52 cards. 
a) what is the probability of being dealt 8 cards from the same suit?
---
# of ways to succeed : 4*13C8*39C5
# of random results: 52C13
P(8 cards of same suit) = [4*13C8*39C5]/52C8
-------------------------------------------- 
b) what is the probability of being dealt 6 hearts? 
# of ways to succeed: [13C6*39C7]/52C13
-------------------------------------------- 
C) If you are dealt 7 hearts, what is the probability that 
your partner has at least 1 heart?
P(at least one heart) = 1 - P(no hearts)
=  1 - {39C13/52C13]
==========================
Cheers,
Stan H.
==============