Question 489680
f(x)=-x^2+2x+8
Find the x and y intercepts
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replace f(x) with y:
y = -x^2+2x+8
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To find y-intercepts set x=0 solve for y:
y = -x^2+2x+8
y = -(0)^2+2(0)+8
y = 0+0+8
y = 8
y-intercept is at (0,8)
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To find x-intercepts set y=0 solve for x:
y = -x^2+2x+8
0 = -x^2+2x+8
0 = x^2-2x-8
0 = (x-4)(x+2)
x = {4, -2}
x-intercepts are at (-2,0) and (4,0)