Question 489178


{{{y = (1/3)x + 3/2}}}

x| y
0| ?
?| 0

here you have to find {{{x}}} and {{{y}}} intercepts

to find {{{x-intercept}}}, set equation to zero

{{{0 = (1/3)x + 3/2}}}

{{{-3/2= (1/3)x }}}

{{{-(3/2)3=x }}}

{{{-(9/2)=x }}}

{{{-4.5=x }}}

to find {{{y-intercept}}}, set {{{x}}} to zero

{{{y = (1/3)*0 + 3/2}}}

{{{y =  3/2}}}

so, your table will be:

---x| y
---0| 1.5
-4.5| 0


{{{ graph( 500, 500, -10, 10, -10, 10,(1/3)x + 3/2) }}}