Question 488850
The sum of two numbers is 47. Twice the larger increased by three times the smaller gives a sum of 106. Find each number.
**
let x=larger number
let y=smaller number
..
x+y=47
x=47-y
..
2x+3y=106
2(47-y)+3y=106
94-2y+3y=106
y=106-94=12
x=47-12=35
ans:
The larger number=35
The smaller number=12