Question 488453
A set of 50 data values has a mean of 41 and a variance of 36.
Note: the standard deviation = sqrt(36) = 6 
I. Find the standard score (z) for a data value = 24.
z(24) = (24-41)/6 = -2.8333
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II. Find the probability of a data value > 24.
P(x > 24) = P(z > -2.8333) = 0.9977
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Cheers,
Stan H.