Question 488409
Let the first digit be x and the second digit be y. Since the sum of the digits is 8, we write the first equation of the system: x+y=8.
Since the difference between the numbers is 36 we write the second equation:
10x+y-(10y+x)=36, simplifying this equation we get:
10(x-y)-(x-y)=36
(x-y)(10-1)=36
9(x-y)=36
x-y=4, is the second equation of the system:{{{system(x+y=8, x-y=4)}}}

Solving this system we get: x=6, and y=2

Answer: The numbers are 62 and 26.