Question 488395
Find an exact solution to the equation below so that 0 < theta < pi. 
(1 + tan(theta))/sin(theta)= 0
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use x for theta
1+tanx/sinx=0
(1+sinx/cosx)/sinx=0
cosx+sinx/cosxsinx=0
cosx+sinx=0
cosx=-sinx
in quadrant II, cos<0, sin>0
x=3&#960;/4