Question 487931
2nd car speed S MPH, then meet at time T (start of 2nd car).
S*T = 50*(T+1) is the distance they each go.
T(S-50)=50
T=50/(S-50) hours.
Another way of looking at it is that the initial distance apart, 50m
is decreasing by their relative speed (S-50):
T=50/(S-50) hours.