Question 487782
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Let *[tex \Large s] represent the measure of an edge of a cube.  Then the area of one side of the cube is *[tex \Large s^2], the volume of the cube is *[tex \Large s^3], the diagonal of a side is *[tex \Large s\sqrt{2}], and the diagonal of the cube is *[tex \Large s\sqrt{3}].


The formula for the diagonal of a side is from Pythagoras:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d_s\ =\ \sqrt{s^2\ +\ s^2}\ =\ \sqrt{2s^2}\ =\ s\sqrt{2}]


The formula for the diagonal of the cube is also from Pythagoras:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d_c\ =\ \sqrt{s^2\ +\ s^2\ +\ s^2}\ =\ \sqrt{3s^2}\ =\ s\sqrt{3}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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