Question 487732
When the equation is in the form{{{ f(x) = ax^2 + bx + c }}},
the x coordinate of the  vertex is at {{{ -b/(2a) }}}
{{{ f(x)=x^2-4x-32 }}}
{{{ a = 1 }}}
{{{ b = -4 }}}
{{{ -b/(2a) = -(-4)/(2*1) }}}
{{{ -b/(2a) = 2 }}}
Now find {{{ f(x) }}}, which is th same as  {{{y}}}
{{{ f(x)=x^2-4x-32 }}}
{{{ y = 2^2 - 4*2 - 32 }}}
{{{ y = 4 - 8 - 32 }}}
{{{ y = -36 }}}
The vertex is at (2,-36)
Here's a plot:
{{{ graph( 400, 400, -5, 10, -40, 5, x^2 - 4x - 32) }}}