Question 487316
the sum of three integers is 232.
a + b + c = 232
:
 the sum of the first and second integers exceeds the third by 92.
a + b = c + 92
a + b - c = 92
:
the third integer is 48 less than the first.
c = a - 48
:
The first and 2nd equations for elimination
a + b + c = 232
a + b - c = 92
----------------subtraction eliminates a and b, find c
2c = 140
c = 70, the 3rd digit
:
The third equation
a - 48 = 70
a = 70 + 48
a = 118, the first digit
:
Find the 2nd digit
118 + b  = 70 + 92
b = 162 - 118
b = 44, the 2nd digit
:
:
Check: 118 + 44 + 70 = 232