Question 487417
 {{{4x+2y=-8}}}.......1



{{{2x+y=-4}}}..........2


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{{{2x+y=-4}}}..........2...solve for {{{y}}}

{{{y=-2x-4}}}...substitute in 1

{{{4x+2(-2x-4)=-8}}}.......1..solve for {{{x}}}

{{{4x-4x-8=-8}}}

{{{4x-4x=-8+8}}}

{{{0=0}}}.......there are an infinite number of solutions and the system is dependent

*[invoke solve_by_graphing 4, 2, -8, 2, 1, -4]