Question 50119
Two cars are leaving Phils house at precisely at 6:20pm. The first car driven by Phil is headed nother. The second car, driven by Roman, is headed south Phil, because he is nat a good citizen is going 20 MPH faster than Roman. If at 7:50 they are exactly 168 miles apart, how fast is each going? 
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Roman car DATA:
rate = x mph ; time= (3/2)hr.; distance= rt= (3/2)x miles
Phil car DATA:
rate = x+20 mph ;  time = (3/2)hr.; distance = rt = (3/2)(x+20)
EQUATION:
distance + distance = 168 miles
(3/2)x+(3/2)(x+20)= 168
3x+30=168
3x=138
x=46 mph (Romans car rate)
x+20= 66 mph (Phil's car rate) 

Cheers
Stan H.