Question 487217

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(2,-1\right)]. So this means that {{{x[1]=2}}} and {{{y[1]=-1}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(6,3\right)].  So this means that {{{x[2]=6}}} and {{{y[2]=3}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(3--1)/(6-2)}}} Plug in {{{y[2]=3}}}, {{{y[1]=-1}}}, {{{x[2]=6}}}, and {{{x[1]=2}}}



{{{m=(4)/(6-2)}}} Subtract {{{-1}}} from {{{3}}} to get {{{4}}}



{{{m=(4)/(4)}}} Subtract {{{2}}} from {{{6}}} to get {{{4}}}



{{{m=1}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(2,-1\right)] and *[Tex \LARGE \left(6,3\right)] is {{{m=1}}}