Question 487008
{{{ V = sqrt(2g*h) }}}
{{{ g = 32 }}} ft/sec 
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(1a)
Square both sides
{{{ V^2 = 2g*h }}}
Divide both sides by {{{ 2g }}}
{{{ h = V^2 / (2g) }}}
{{{ h = V^2 / 64 }}}
(1b)
given:
{{{ h = 80 }}}
{{{ 80 = V^2 / 64 }}}
Multiply both sides by {{{64}}}
{{{ V^2 = 5120 }}}
{{{ V = sqrt(5120) }}}
{{{ V }}} is between {{{71}}} and {{{72}}} ft/sec
That is the velocity of water that is 
needed to reach a height of {{{80}}} ft
A pump that projects water with velocity
of 70 ft/sec will not reach a height of {{{ 80 }}} ft
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The height that the water will reach is:
{{{ h = V^2/64 }}}
{{{ h = 70^2 / 64 }}}
{{{ h = 4900 / 64 }}}
{{{ h = 76.56 }}} ft
This is {{{ 3.44 }}} ft short