Question 486971
You cannot divide by zero. So the denominator cannot be equal to zero. If it were, then 



{{{(x+1)(x^2+1)=0}}} 



which means that



{{{x+1=0}}} or {{{x^2+1=0}}} 



Solve the first equation to get {{{x=-1}}}. Solve the second equation to get {{{x=i}}} or {{{x=-i}}}. 



Ignore the last two answers (since we're only concerned about real numbers).



So if {{{x=-1}}}, then the entire denominator is zero.



So we must exclude this value from the domain.



So the domain is *[Tex \LARGE \left(-\infty,-1\right)\cup\left(-1,\infty\right)]