Question 486918
{{{f(x) = (3x-1)/((x+3)(x-1))}}}


{{{x}}} can take {{{any}}} {{{real}}} number {{{except}}} {{{-3}}} or {{{1}}}  since {{{x = -3}}} or {{{x=1}}} would make the denominator {{{equal}}} to {{{zero}}} and the division by zero is not allowed in mathematics. 


Hence the domain in interval notation is given by

({{{-infinity}}} , {{{-3}}}) U ({{{-3}}},{{{1}}}) U ({{{1}}} ,{{{infinity}}})