<PRE><B>Question 486294</B>
Give exact and approximate solutions to three decimal places: 
y^2-2y+1=100.
***
To find the zeros you can either factor or use the quadradic formula.
Factoring: set expression = zero, use trial and error method, then check using FOIL.
y^2-2y-99=0
..
Quadratic formula: {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} For given equation, a=1, b=-2, and c=-99
ans:
y=-9 or 11</PRE>