Question 486703
{{{(x^2+19)/(2-x)}}} for {{{x=3i}}}
{{{((3i)^2+19)/(2-3i)=(-9+19)/(2-3i)=10/(2-3i)}}}
multiply numerator and denominator by {{{(2+3i)}}}
{{{10/(2-3i)=(10*(2+3i))/((2-3i)*(2+3i))=(20+30i)/(4-9i^2)=(20+30i)/13=20/13+(30/13)i}}}