Question 486698
Use Ohm's Law E=I*R
 
{{{E=I*R=(2-3*i)*(3+5*i)}}}
{{{E=6+10*i-9*i-15*i^2}}} and since {{{i^2=-1}}} this can be simplified to 
{{{E=6+1*i+15=(21+i) volts}}}

One small comment. Here, R=(3+5i) which should strictly be called Z (the 'Impedance' which is complex) where R is the Real part of Z...

merv