Question 486585
{{{(6x^3y^(-1))/(4x^(-2)y)^(-2)=6x^3y^(-1)*(4x^-2y)^2=6x^3y^(-1)*16x^(-4)y^2=96x^(3-4)y^(-1+2)=96x^(-1)y^1=96y/x}}}