Question 50109
They want us to identify the slope of m, and the y-intercept, b, for each line. Then graph . I looked at the examples put still can't figure it out the same with example -2x=8+4y , just can't find the way to solve the problem
STD.FORM IS 
Y=MX+C...WHERE M=SLOPE...C=Y INTERCEPT
-2X=8+4Y
4Y=-2X-8
Y=(-2/4)X+(-8/4)=-X/2-2......HENCE 
M=-2/4=-1/2...Y INTERCEPT = -8/4=-2
TO GRAPH GIVE VALUES TO X ,FIND Y FROM THE EQN. & PLOT
X..............0....................2........................-4............ETC
Y=(-X/2)-2....-2....................-3........................0........ETC
{{{ graph( 300, 300, -10, 10, -10, 10, -(x/2)-2) }}}