Question 486670
a(x+c)=b(x-c) solve for x

first step: distribute
 a(x+c)=b(x-c) ----> ax + ac = bx - bc

second: get your ¨x¨ on one side
 ax + ac = bx - bc ----> ax - bx = -bc - ac

third: common factor
 ax - bx = -bc - ac ----> x ( a - b) = -c ( b + a )

forth: get ¨x¨ by itself (dividing both sides by the coefficient in front of x)
 x ( a - b) = -c ( b + a ) ----> x = (-c ( b + a)/ (a - b))