Question 486510
The hyperbola with center at (4, 5), with vertices at (0, 5) and (8, 5), with b = 2.
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Based on data given, this is an equation of a hyperbola with horizontal transfer axis of the standard form: (x-h)^2/a^2-(y-k)^2/b^2=1
Center: (4,5) 
Length of horizontal transverse axis: 8-5=3=2a
a=3/2
a^2=9/4
b=2
b^2=4
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Equation: (x-4)^2/(9/4)-(y-5)^2/4=1
or 4(x-4)^2/9-(y-5)^2/4=1