Question 486311
x1		y1	x2	y2				
3		2	-6	8				
								
slope m =		(y2-y1)/(x2-x1)						
(	8	-	2	)/(	-6	-	3	) 
(	6	/	-9	)  				
m=		-  2/ 3						 
								
Plug value of  the slope  and point 			(	3	,	2	) in	
Y 	=	m	x 	+	b			
2.00	=	-2    	+	b				
b=	2	-	-2    					
b=	4      							
So the equation  will be								
Y 	=	- 2/3	x 	+	4 

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1	y  	=	-3/5	x	+	-4	
Divide by 	1						
	y  	=	-3/5	x		-4	
Compare this equation with y=mx+b							
slope m =	-3/5			0.8			
The slope of a line parallel to the above line will be the same							
The slope of the required line will be -3/5				
m=	-0.6	,point	(	-5	,	5	)
Find b by plugging the values of m & the point in							
y=mx+b							
5	=	3.00	+	b			
b=	2						
m=	-3/5						
Plug value of  the slope  and b	in y = mx +b		
The required equation is	y  	=	-3/5	x	+	2
		y  	=	-  3/ 5	x	+	2 

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y  	=	-2/5	x		-3			
Compare this equation with y=mx+b									
slope m =	-2/5								
									
The slope of a line perpendicular to the above line will be the negative reciprocal									
m1*m2=-1									
The slope of the required line will be 	5/2	
									
m=	5/2	,point	(-4,-7	)		
Find b by plugging the values of m & the point in									
y=mx+b									
-7	=	-10.00	+	b					
b=	3								
m=	5/2								
The required equation is y  	=	5/ 2	x	+	3      		
     



   			
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