<PRE><B>Question 486108</B>
Yes, you are right that


*[tex \LARGE \sqrt{-60} = \sqrt{10}\sqrt{6}\sqrt{-1}]. However, I would write it as


*[tex \LARGE \sqrt{-60} = \sqrt{60}\sqrt{-1} = 2\sqrt{15}\sqrt{-1}]


By definition, the imaginary number i is defined for sqrt(-1) so


*[tex \LARGE \sqrt{-60} = 2\sqrt{15}i]</PRE>