Question 486050
y^2+6y+10=0 solve by completing the square


{{{y^2 + 6y + 10 = 0}}} 


{{{y^2 + 6y = -10}}} ----- Subtracting "c" 


{{{y^2 + 6y + 9 = - 10 + 9}}} ------ Halving "b, squaring it, and then adding the result to both sides of equation


{{{(y + 3)^2 = - 1}}}


{{{sqrt((y + 3)^2) = _+-sqrt(-1)}}} ----- taking square root of each side


{{{y + 3 = _+-i}}}


{{{y = - 3+-i}}} ---- Subtracting 3 from each side


{{{highlight_green(y = - 3+-i)}}} ----- {{{highlight_green(y = - 3 + i)}}} or  {{{highlight_green(y = - 3 - i)}}}